Histograms — Unequal Classes
Progressive test · Grades 5–9 · Frequency Density Mastery
📐 Formula Reference
FD = Frequency ÷ Class Width
Use to find bar height
Frequency = FD × Class Width
Area of bar = Frequency
Questions 1–5 · Grades 5–6 · Core FD Calculations
A class interval has a Frequency of 24 and a Class Width of 4. Calculate the Frequency Density.
| Class Width | Frequency | Frequency Density |
|---|---|---|
| 4 | 24 | ? |
The class interval 10 ≤ t < 25 has a frequency of 45. Calculate the Frequency Density.
| Class Interval | Class Width | Frequency | Frequency Density |
|---|---|---|---|
| 10 ≤ t < 25 | 15 | 45 | ? |
The class interval 30 ≤ w < 50 has a frequency of 100. Calculate the Frequency Density.
| Interval | Freq | FD |
|---|---|---|
| 30 ≤ w < 50 | 100 | ? |
A histogram bar has a Frequency Density of 3.5 and the class width is 8. Calculate the Frequency.
| Class Width | FD | Frequency |
|---|---|---|
| 8 | 3.5 | ? |
⚠️ TRAP: Never read bar HEIGHT as Frequency. In histograms, AREA = Frequency.
A bar covers the interval 20 ≤ x < 35 and has a Frequency Density of 4. Calculate the Frequency.
| Interval | Class Width | FD | Frequency |
|---|---|---|---|
| 20 ≤ x < 35 | 15 | 4 | ? |
⚠️ TRAP: Always subtract to find Class Width — do not assume it equals 10.
Questions 6–10 · Grades 6–7 · Reading & Completing Histograms
The table below is incomplete. Using the histogram (bar heights given), find the missing frequency for 40 ≤ t < 60.
| Interval | Class Width | FD (bar height) | Frequency |
|---|---|---|---|
| 20 ≤ t < 30 | 10 | 5 | 50 |
| 30 ≤ t < 40 | 10 | 8 | 80 |
| 40 ≤ t < 60 | 20 | 3 | ? |
| 60 ≤ t < 70 | 10 | 4 | 40 |
⚠️ TRAP: The bar for 40 ≤ t < 60 is WIDER — same height ≠ same frequency!
The histogram shows bars for the weight (kg) of parcels. The bar for 2 ≤ w < 5 has a height (FD) of 6. Find the frequency for this class.
| Interval | Class Width | FD | Frequency |
|---|---|---|---|
| 0 ≤ w < 2 | 2 | 8 | 16 |
| 2 ≤ w < 5 | 3 | 6 | ? |
| 5 ≤ w < 8 | 3 | 4 | 12 |
The table is partially completed. The total number of students surveyed is 200. Use this to find the missing frequency for 50 ≤ m < 80.
| Interval | Class Width | FD | Frequency |
|---|---|---|---|
| 0 ≤ m < 20 | 20 | 2 | 40 |
| 20 ≤ m < 50 | 30 | 3 | 90 |
| 50 ≤ m < 80 | 30 | ? | ? |
| 80 ≤ m < 100 | 20 | 1 | 20 |
⚠️ TRAP: Use the TOTAL to find the missing frequency first, THEN calculate FD.
Complete the histogram. The class 60 ≤ t < 65 has a frequency of 35. What height should the bar be drawn at?
| Interval | Class Width | Frequency | FD (bar height) |
|---|---|---|---|
| 50 ≤ t < 55 | 5 | 20 | 4 |
| 55 ≤ t < 60 | 5 | 30 | 6 |
| 60 ≤ t < 65 | 5 | 35 | ? |
| 65 ≤ t < 75 | 10 | 40 | 4 |
The frequency table below has two missing FD values. Calculate both bar heights for 10 ≤ x < 30 and 50 ≤ x < 70.
| Interval | Class Width | Frequency | FD |
|---|---|---|---|
| 0 ≤ x < 10 | 10 | 15 | 1.5 |
| 10 ≤ x < 30 | 20 | 60 | ? |
| 30 ≤ x < 50 | 20 | 80 | 4 |
| 50 ≤ x < 70 | 20 | 30 | ? |
Questions 11–15 · Grades 8–9 · Estimation, Ratio & Median
The class interval 60 ≤ w < 80 has a frequency of 40 (class width = 20, FD = 2). Estimate the number of people with weight between 65 kg and 80 kg. Assume uniform distribution within the class.
| Interval | Class Width | FD | Frequency |
|---|---|---|---|
| 60 ≤ w < 80 | 20 | 2 | 40 |
⚠️ TRAP: You CANNOT read 65–80 directly from the histogram — you must SPLIT the bar using proportion.
Using the table below, estimate how many people have a time between 25 and 45 minutes. Assume uniform distribution within each class.
| Interval | Class Width | FD | Frequency |
|---|---|---|---|
| 20 ≤ t < 30 | 10 | 4 | 40 |
| 30 ≤ t < 50 | 20 | 3 | 60 |
⚠️ TRAP: 25–45 crosses a class boundary — always handle each class SEPARATELY.
Bar A covers 10 ≤ x < 30 with Frequency Density = 5. Bar B covers 30 ≤ x < 40 with unknown frequency. The area of Bar A is twice the area of Bar B. Find the frequency of Bar B.
| Bar | Interval | Class Width | FD | Frequency (Area) |
|---|---|---|---|---|
| A | 10 ≤ x < 30 | 20 | 5 | ? |
| B | 30 ≤ x < 40 | 10 | ? | ? |
⚠️ TRAP: 'Area of bar' = Frequency. The ratio of AREAS = ratio of FREQUENCIES.
The frequency of class 0 ≤ t < 20 is three times the frequency of class 20 ≤ t < 30. The FD of the first class is 4.5. Find the FD of the second class.
| Interval | Class Width | FD | Frequency |
|---|---|---|---|
| 0 ≤ t < 20 | 20 | 4.5 | ? |
| 20 ≤ t < 30 | 10 | ? | ? |
⚠️ TRAP: Never assume FDs are in the same ratio as frequencies — class widths differ!
The histogram below shows the distribution of 160 students' exam scores. Estimate the median score.
| Interval | Class Width | FD | Frequency |
|---|---|---|---|
| 0 ≤ s < 20 | 20 | 1 | 20 |
| 20 ≤ s < 40 | 20 | 2 | 40 |
| 40 ≤ s < 60 | 20 | 3 | 60 |
| 60 ≤ s < 80 | 20 | 1.5 | 30 |
| 80 ≤ s < 100 | 20 | 0.5 | 10 |
⚠️ TRAP: Don't just find the middle CLASS — you must INTERPOLATE within the class.
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