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1.1.3

Binomial Applications lesson

Chapter 1 · Algebraic Proofs · Concept 1

1-3  Applications of the Binomial Theorem

So far you have used the binomial theorem to find a coefficient. Now you will use it to prove that something is true.

Guiding question

If you know what (1 + x)n opens out to, what can you learn by putting a number in for x?

Learning outcome. Employs the binomial theorem in mathematical and computational applications.

A question here does not ask you to find a number. It gives you a long line of nCr terms and says prove this is true.

That sounds much harder than it is. Every single one is the same two moves:

Move 1

Write out (1 + x)n with the binomial theorem.

This line is the same every time. You never change it.

Move 2

Put the right number in for x.

This is the only part that changes. It is the whole lesson.

The line you always start from

(1 + x)n = nC0 + nC1x + nC2x2 + …… + nCnxn

Then put a suitable number in for x to get the equality you were asked for.

Why 1 + x and not something else? Because 1 to any power is still 1. So the first part disappears from every term and only x is left to work with.

Look at the numbers sitting in front of the nCr terms. They are the powers of x, so they tell you what x is.

What you see in frontSo x isAnd the answer is (1 + x)ⁿ
1, 1, 1, 1, … (nothing written)12ⁿ
1, −1, 1, −1, … (signs swap)−10
1, 2, 2², 2³, …23ⁿ
1, −2, 2², −2³, …−2(−1)ⁿ
1, ½, ¼, ⅛, … with swapping signs−1/2(1/2)ⁿ

Every question on this page is one of these five rows. Learn to read the row and you are done.

Pick a value for x and add the terms up yourself. The long way and the short way always land on the same number. That is what a proof of this kind is saying.

Put 1 in place of x, one term at a time. Watch the running total.

1+5×(1)1+10×(1)2+10×(1)3+5×(1)4+1×(1)5

running total after 1 term: 1

The short way: (1 + 1)5 = 32— which is 2ⁿ with n = 5

every term is added

Prove that nC0 + nC1 + nC2 + …… + nCn = 2n

  1. 1

    Look at what is in front of each term.

    1, 1, 1, …… — there is nothing written in front of any of them

    Row one of the table above. Nothing in front means x = 1.

Step 1 of 6

Work with a partner. Do this one together, then talk about how you knew what x was. Send it to your notebook first — it is easier to work on paper.

Prove that nC0 − nC1 + nC2 − …… + (−1)n nCn = 0

  1. 1

    Read the signs.

    +   −   +   −   ……

    They swap every time. Row two of the table: that means x = −1.

Step 1 of 6

Prove that these equalities hold.

By using the binomial theorem, prove that (8n − 1) is divisible by 7, where n is a positive integer.

Substitute on BOTH sides.

If you put x = 1 into the right side you must put it into (1 + x)ⁿ as well. Changing one side only is not an equation any more, and it is the commonest way to lose every mark on the question.

Signs that swap mean a negative x.

+ − + − comes from x = −1. + then powers of 2 with swapping signs comes from x = −2. Read the signs before you write anything.

Dividing by 2 is multiplying by 1/2.

Exercise 3 has nCr ⁄ 2ʳ, which looks nothing like a power of x until you see it as (1/2)ʳ. With the swapping signs that makes x = −1/2.

n must be positive.

The Try proof ends with 0ⁿ = 0, and that is only true when n is 1 or more. At n = 0 the sum is 1, not 0 — which is exactly why the question says n is a positive integer.

That is Concept 1 finished. The review quiz covers all three lessons.

Keep reading — this lesson marks itself done automatically.