Quiz: Section 1.1 Length and Time
Complete exam-style questions covering Paper 2 (MCQ), Paper 4 (Structured), and Paper 6 (Alternative to Practical)
Paper 2: Multiple Choice Questions
Select the best answer for each question. Click "Show Explanation" to see why distractors are wrong.
1. A student measures the diameter of a wire using a micrometer screw gauge. The main scale reading is 3.5 mm and the thimble scale shows 28. If the instrument has 50 divisions on the thimble scale and each rotation moves 0.5 mm, what is the diameter?
2. A vernier caliper has a positive zero error of 0.04 cm. When measuring an object, the main scale reads 4.6 cm and the vernier scale coincides at the 7th mark. What is the correct length?
3. A student times 20 complete oscillations of a pendulum and records 32.0 s. What is the period of the pendulum to the appropriate number of significant figures?
4. Which measuring instrument would be MOST suitable for measuring the internal diameter of a glass tube of approximately 8 mm?
5. A student measures a length as 24.7 mm using a ruler marked in mm. Another student measures the same length as 24.73 mm using vernier calipers. Which statement is correct?
Paper 4: Structured Questions
Answer all parts. Mark schemes show keywords required for full marks.
Question 1: Zero Error Analysis and Correction
(a) Define the term 'zero error' in the context of measuring instruments.[2 marks]
(b) A vernier caliper shows the diagram below when its jaws are completely closed. State whether this is a positive or negative zero error and determine its magnitude.[3 marks]
(c) The same vernier caliper is used to measure a metal rod. The main scale reads 3.2 cm and the 8th vernier mark coincides with a main scale mark. Calculate the corrected length of the rod.[4 marks]
(d) Explain why it is important to check for zero error before taking measurements.[2 marks]
Question 2: Measurement of Small Distances - Micrometer Application
(a) State why a micrometer screw gauge is preferred over a ruler when measuring the diameter of a thin wire.[2 marks]
(b) A student measures the diameter of a wire at 5 different points and records: 0.54 mm, 0.53 mm, 0.55 mm, 0.53 mm, 0.54 mm. Calculate the average diameter and explain why taking multiple measurements is important.[4 marks]
(c) The wire is uniform. Suggest and explain one reason why the student's measurements might show variation.[2 marks]
Paper 6: Alternative to Practical
Data analysis and instrument reading question. Focus: Vernier Caliper precision.
Reading Precision Instruments - Vernier Caliper
You are provided with a vernier caliper to measure the thickness of a glass slide.
Equipment Information:
Vernier caliper: Main scale divisions = 1 mm, Vernier scale = 10 divisions
Therefore: Vernier precision = 0.1 mm or 0.01 cm
Diagram Reference:
Note: Red line shows vernier zero position (3rd mark from left)
(a) The diagram below shows the vernier caliper when its jaws are closed. Determine if there is a zero error and state its value.[2 marks]
(b) The diagram below shows the vernier caliper measuring the glass slide. Record the reading shown.[3 marks]
(c) Calculate the corrected thickness of the glass slide.[2 marks]
(d) State the precision of the vernier caliper used.[1 marks]
(e) The student takes 3 readings at different positions on the glass slide: 0.46 cm, 0.45 cm, 0.46 cm (all raw readings). After correcting for zero error, calculate the average thickness.[3 marks]
Exam Technique Summary - Length & Time
Core Learning Outcomes (1.1):
- ✓ Use rulers and measuring cylinders correctly
- ✓ Use clocks and timers for intervals
- ✓ Calculate averages from multiple measurements
Supplement (Extended Only):
- ✓ Understand micrometer usage for small distances
- ✓ Apply zero error corrections systematically
- ✓ Determine precision and significant figures
Mark Scheme Keywords to Remember:
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